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🌍 Gravitation & Central Force Motion

🌍 Gravitation & Central Force Motion

UG Physics (Honours) Notes


⭐ Newton’s Law of Gravitation

Newton stated that every two masses in the universe attract each other with a force:F=Gm1m2r2F = G\frac{m_1 m_2}{r^2}F=Gr2m1​m2​​

Where:
G=6.674×1011Nm2/kg2G = 6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2G=6.674×10−11Nm2/kg2

Force acts along the line joining the centers of the masses — a central force.


🔹 Gravitational Potential Energy

Work done to bring a mass mmm from infinity to a distance rrr:U(r)=GMmrU(r) = -\frac{GMm}{r}U(r)=−rGMm​

Negative sign → Gravity is an attractive force.


🔹 Inertial & Gravitational Mass

Mass TypeMeaningExperiment
Inertial MassResists accelerationNewton’s 2nd Law
Gravitational MassMeasures gravitational forceCavendish type
Both are proven to be equivalent → Principle of Equivalence (Einstein).

🔸 Gravitational Field and Potential of Spherical Objects

👉 Spherical Shell

  • Inside shell: g=0g = 0g=0 Field is zero → hollow cavity has no gravitational effect.
  • Outside shell:
    Acts like a point mass at center: g=GMr2g = \frac{GM}{r^2}g=r2GM​

👉 Solid Sphere

  • Outside: Point mass behaviour g=GMr2g = \frac{GM}{r^2}g=r2GM​
  • Inside: Proportional to radius g=GMrR3g = \frac{GMr}{R^3}g=R3GMr​

🚀 Central Force Motion

A force which always acts along the radius vector and depends only on distance:F(r)=F(r)r^\vec{F}(r) = F(r)\hat{r}F(r)=F(r)r^

Examples: Gravitational force, Electrostatic force.


🔸 Two-Body Problem → One-Body Reduction

Two masses m1,m2m_1, m_2m1​,m2​ interacting through central force are reduced to:

  • Motion of center of mass
  • Relative motion of reduced mass

μ=m1m2m1+m2\mu = \frac{m_1 m_2}{m_1 + m_2}μ=m1​+m2​m1​m2​​

The problem becomes a single particle of mass μμμ moving under a central potential.


✳ Differential Equation of Motion

μr¨=F(r)\mu \ddot{\vec{r}} = \vec{F}(r)μr¨=F(r)


🌟 First Integrals of Motion

1️⃣ Angular Momentum ConservationL=μr2θ˙=constant\vec{L} = \mu r^2 \dot{\theta} = \text{constant}L=μr2θ˙=constant

2️⃣ Energy ConservationE=12μr˙2+L22μr2+U(r)=constantE = \frac{1}{2}\mu\dot{r}^2 + \frac{L^2}{2\mu r^2} + U(r) = \text{constant}E=21​μr˙2+2μr2L2​+U(r)=constant


⚡ Power Law Potentials

U(r)rnU(r) \propto r^nU(r)∝rn

Examples:

  • Inverse square law → U(r)1/rU(r) \propto -1/rU(r)∝−1/r
  • Harmonic oscillator → U(r)r2U(r) \propto r^2U(r)∝r2

🌞 Kepler’s Laws of Planetary Motion

Derived from Newton’s gravitation:

1️⃣ Law of Orbits
Planets move in elliptical orbits, Sun at one focus.

2️⃣ Law of Areas
Equal areas in equal times → conservation of angular momentum.

3️⃣ Law of PeriodsT2a3T^2 \propto a^3T2∝a3

Where TTT = time period and aaa = semi-major axis.


🛰 Satellite Motion

Orbital Velocity:

v0=GMR+hv_0 = \sqrt{\frac{GM}{R+h}}v0​=R+hGM​​

Escape Velocity:

ve=2GMRv_e = \sqrt{\frac{2GM}{R}}ve​=R2GM​​


⭐ Geosynchronous Orbit

  • Period = 24 hours
  • Always above same point on Earth
  • Used for satellite TV & communication

Altitude approx: 36,000 km


⭐ Weightlessness in Orbit

Astronauts are in free fall around Earth → no normal reaction force.
Hence, they feel weightless.


🌐 Global Positioning System (GPS)

  • Network of 24 satellites
  • Provides accurate position using signal triangulation
  • Used in: Navigation, defense, mobile tracking

👨‍🚀 Physiological Effects on Astronauts

EffectReason
Muscle weakeningNo muscle load in microgravity
Bone density lossCalcium release due to low stress
Fluid shift to headLack of gravity pull
Orientation problemsNo up-down reference

Solution: Exercise, nutritional support, artificial gravity research.


🔍 Quick Summary

TopicKey Formula / Idea
Gravitational ForceF=Gm1m2r2F = G \frac{m_1 m_2}{r^2}F=Gr2m1​m2​​
Potential EnergyU=GMmrU=-\frac{GMm}{r}U=−rGMm​
Escape Velocityve=2GMRv_e = \sqrt{\frac{2GM}{R}}ve​=R2GM​​
Kepler’s 3rd LawT2a3T^2 ∝ a^3T2∝a3
Two-body → one-bodyReduced mass μ\muμ

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