Electric Field and Electric Potential

(Electrostatics โ€“ Physics Honours Notes)


๐Ÿ“Œ 1. Electric Field (๐„โƒ— )

Electric field represents the influence of a charge on the surrounding space.

Definition

Electric field at a point is the force experienced per unit positive test charge.Eโƒ—=Fโƒ—q\vec{E} = \frac{\vec{F}}{q}E=qFโ€‹

Electric Field Lines

  • Represent direction of electric field.
  • Originates from positive and ends on negative charges.
  • Never intersect.
  • Density of lines = strength of electric field.

Electric Flux

Flow of electric field lines through a surface.ฯ•E=Eโƒ—โ‹…Aโƒ—=EAcosโกฮธ\phi_E = \vec{E} \cdot \vec{A} = EA \cos\thetaฯ•Eโ€‹=Eโ‹…A=EAcosฮธ

Measured in Nยทmยฒ/C


๐Ÿ“Œ 2. Gauss’s Law

Total electric flux through a closed surface is equal to charge enclosed divided by ฮตโ‚€:โˆฎEโƒ—โ‹…dAโƒ—=Qenclosedฯต0\oint \vec{E} \cdot d\vec{A} = \frac{Q_{\text{enclosed}}}{\epsilon_0}โˆฎEโ‹…dA=ฯต0โ€‹Qenclosedโ€‹โ€‹

Applications of Gaussโ€™s Law


โญ A) Spherical Symmetry โ€” Charged Sphere

  1. Point charge or uniformly charged sphere (outside sphere)

E=14ฯ€ฯต0Qr2E = \frac{1}{4\pi\epsilon_0}\frac{Q}{r^2}E=4ฯ€ฯต0โ€‹1โ€‹r2Qโ€‹

  1. Inside a uniformly charged sphere

E=Qr4ฯ€ฯต0R3E = \frac{Qr}{4\pi\epsilon_0 R^3}E=4ฯ€ฯต0โ€‹R3Qrโ€‹

(โˆ r โ‡’ zero at center)


โญ B) Cylindrical Symmetry โ€” Infinite Line of Charge

E=ฮป2ฯ€ฯต0rE = \frac{\lambda}{2\pi\epsilon_0 r}E=2ฯ€ฯต0โ€‹rฮปโ€‹


โญ C) Planar Symmetry โ€” Infinite Plane Sheet

E=ฯƒ2ฯต0E = \frac{\sigma}{2\epsilon_0}E=2ฯต0โ€‹ฯƒโ€‹

(Independent of distance!)


๐Ÿ“Œ 3. Conservative Nature of Electrostatic Field

  • Work done in a closed path = 0

โˆฎEโƒ—โ‹…dlโƒ—=0\oint \vec{E} \cdot d\vec{l} = 0โˆฎEโ‹…dl=0

  • Electric field = negative gradient of potential

Eโƒ—=โˆ’โˆ‡V\vec{E} = -\nabla VE=โˆ’โˆ‡V


๐Ÿ“Œ 4. Electric Potential (V)

Work done by external force in bringing a unit positive charge from infinity to a point.V=WqV = \frac{W}{q}V=qWโ€‹

Potential due to a Point Charge

V=14ฯ€ฯต0QrV = \frac{1}{4\pi\epsilon_0} \frac{Q}{r}V=4ฯ€ฯต0โ€‹1โ€‹rQโ€‹


Electric Potential and Field of a Dipole

Electric dipole: two equal & opposite charges separated by distance 2a
Dipole moment:pโƒ—=qโ‹…2a\vec{p} = q \cdot 2apโ€‹=qโ‹…2a

On axial line:Vaxial=14ฯ€ฯต0pr2V_{\text{axial}} = \frac{1}{4\pi\epsilon_0} \frac{p}{r^2}Vaxialโ€‹=4ฯ€ฯต0โ€‹1โ€‹r2pโ€‹

On equatorial line:Vequatorial=0V_{\text{equatorial}} = 0Vequatorialโ€‹=0

Force on dipole in uniform field:Fโƒ—=0\vec{F} = 0F=0

Torque:ฯ„โƒ—=pโƒ—ร—Eโƒ—\vec{\tau} = \vec{p} \times \vec{E}ฯ„=pโ€‹ร—E


๐Ÿ“Œ 5. Laplace & Poisson Equations

โˆ‡2V=0(Laplace in charge-free region)\nabla^2 V = 0 \quad (\text{Laplace in charge-free region})โˆ‡2V=0(Laplace in charge-free region) โˆ‡2V=โˆ’ฯฯต0(Poisson with charge)\nabla^2 V = -\frac{\rho}{\epsilon_0} \quad (\text{Poisson with charge})โˆ‡2V=โˆ’ฯต0โ€‹ฯโ€‹(Poisson with charge)


๐Ÿ“Œ 6. Uniqueness Theorem

The solution of electrostatic potential satisfying:

  1. Poisson/Laplace equation and
  2. Boundary conditions
    is unique.

๐Ÿ“Œ 7. Method of Images

Used to solve problems involving conductors by replacing boundaries with imaginary charges.

Applications

1๏ธโƒฃ Point charge near infinite grounded conducting plane
โ†’ Replace by image charge of equal magnitude but opposite sign behind plane.
Helps calculate:

  • Potential
  • Force on charge
  • Surface charge density

2๏ธโƒฃ Charge near grounded conducting sphere
โ†’ Image charge placed inside sphere at a specific location
Ensures potential on surface remains zero.


๐Ÿ“Œ 8. Electrostatic Energy

System of Point Charges

U=12โˆ‘iqiViU = \frac{1}{2}\sum_{i} q_i V_iU=21โ€‹iโˆ‘โ€‹qiโ€‹Viโ€‹

Charged Isolated Sphere

U=12Q24ฯ€ฯต0RU = \frac{1}{2} \frac{Q^2}{4\pi\epsilon_0 R}U=21โ€‹4ฯ€ฯต0โ€‹RQ2โ€‹

ORU=12QVU = \frac{1}{2} QVU=21โ€‹QV


๐Ÿ“Œ 9. Conductors in Electrostatic Field

  • Electric field inside a conductor = 0
  • Excess charge resides only on surface
  • Surface is an equipotential
  • Surface charge density:

ฯƒ=ฯต0EโŠฅ\sigma = \epsilon_0 E_\perpฯƒ=ฯต0โ€‹EโŠฅโ€‹

Force on conductor surface:f=ฯƒ22ฯต0f = \frac{\sigma^2}{2\epsilon_0}f=2ฯต0โ€‹ฯƒ2โ€‹


โœจ Key Highlights (Quick Revision)

ConceptKey Result
E-field from potentialEโƒ—=โˆ’โˆ‡V\vec{E} = -\nabla VE=โˆ’โˆ‡V
Gaussโ€™s lawโˆฎEโƒ—โ‹…dAโƒ—=Qฯต0\oint \vec{E}\cdot d\vec{A} = \frac{Q}{\epsilon_0}โˆฎEโ‹…dA=ฯต0โ€‹Qโ€‹
Infinite sheet fieldE=ฯƒ2ฯต0E = \frac{\sigma}{2\epsilon_0}E=2ฯต0โ€‹ฯƒโ€‹
Inside charged sphereEโˆrE \propto rEโˆr
ConductorsEinside=0E_{\text{inside}} = 0Einsideโ€‹=0
Dipole torqueฯ„=pEsinโกฮธ\tau = pE\sin\thetaฯ„=pEsinฮธ

๐Ÿ“˜ Conclusion

This chapter explains how charges create fields and potentials in space, and how energy and forces are stored or applied through electrostatic interactions. Gaussโ€™s law and boundary conditions provide powerful tools to solve symmetric electrostatic problems effectively.

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